iPad Pro 11 (M4) · 128GB (Silver)
128GB · 2024
iPad Pro 13 (M4) · 128GB (Silver)
128GB · 2024
iPad Pro 13 (M4) · 128GB (Silver) takes it — here’s why.
In our weighted Specdex score, iPad Pro 11 (M4) · 128GB (Silver) lands at 92 and iPad Pro 13 (M4) · 128GB (Silver) at 94. That puts iPad Pro 13 (M4) · 128GB (Silver) ahead by 2 points — a narrow margin driven mostly by its strengths in the categories below.
Pick iPad Pro 11 (M4) · 128GB (Silver) if…
- ✓Portable creative canvas
- ✓Strong SoC
- ✓App ecosystem matures per year
Pick iPad Pro 13 (M4) · 128GB (Silver) if…
- ✓Portable creative canvas
- ✓Strong SoC
- ✓App ecosystem matures per year
Score breakdown
Specs side-by-side
| Spec | iPad Pro 11 (M4) · 128GB (Silver) | iPad Pro 13 (M4) · 128GB (Silver) |
|---|---|---|
| Storage | 128GB | 128GB |
| Release year | 2024 | 2024 |
iPad Pro 11 (M4) · 128GB (Silver)
- +Portable creative canvas
- +Strong SoC
- +App ecosystem matures per year
- −Keyboard/pen extra cost
- −RAM often soldered
- −Mid-tier cameras
iPad Pro 13 (M4) · 128GB (Silver)
- +Portable creative canvas
- +Strong SoC
- +App ecosystem matures per year
- −Keyboard/pen extra cost
- −RAM often soldered
- −Mid-tier cameras
FAQ: iPad Pro 11 (M4) · 128GB (Silver) vs iPad Pro 13 (M4) · 128GB (Silver)
Which is better, iPad Pro 11 (M4) · 128GB (Silver) or iPad Pro 13 (M4) · 128GB (Silver)? +
iPad Pro 13 (M4) · 128GB (Silver) scores 94 on our weighted rubric — ahead by 2. Your best pick depends on the sub-scores above.
Is iPad Pro 11 (M4) · 128GB (Silver) worth the price? +
At $1,099, iPad Pro 11 (M4) · 128GB (Silver) delivers a Specdex score of 92 — strongest in performance.
Is iPad Pro 13 (M4) · 128GB (Silver) worth the price? +
At $1,399, iPad Pro 13 (M4) · 128GB (Silver) delivers a Specdex score of 94 — strongest in performance.
Does iPad Pro 11 (M4) · 128GB (Silver) or iPad Pro 13 (M4) · 128GB (Silver) last longer? +
Based on our long-term update and support ratings, both ship with multi-year support. Battery and reliability scores are visible in the breakdown above.